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# Category: Statistics

## A random variable X has a probability distribution as follows: X | 0 1 2 3 P(X) | 2k 3k 13k 2k What is the possible value of k: (STA301)

0.01 0.03 0.05 0.07

## For the independent events A and B if P (A) = 0.25, P (B) =0.40 then P (A and B) =…… Select correct option: (STA301)

0.65 0.1 0.50 0.15

## If the second moment ratio is less than 3 the distribution will be: (STA301)

Mesokurtic Leptokurtic Platykurtic None of these

## If P (A) = 0.3 and P (B) = 0.5, find P (A/B) where ‘A’ and ‘B’ are independent: (STA301)

0.3 0.5 0.8 0.15

## Suppose the test scores of 600 students are normally distributed with a mean of 76 and standard deviation of 8. The number of students scoring between 70 and 82 is: (STA301)

272 164 260 328

## The moment ratios of normal distribution come out to be: (STA301)

0 and 1 0 and 2 0 and 3 0 and 4

## When we draw the sample with replacement, the probability distribution to be used is: (STA301)

Binomial Hypergeometric Binomial & hypergeometric Poisson

## The binomial distribution is negatively skewed when: (STA301)

p>q p<q p=q p=q=1/2

## A random sample of n=25 values gives sample mean 83. Can this sample be regarded as drawn from a normal population with µ= 80 and s= 7? In this question the alternative hypothesis will be (STA301)

H1: µ = 80 H1: µ = 80 H1: µ is not equal to 80 H1: µ > 80 H1: µ <80 H1: µ > 80 H1: µ <80